4[3-(2-8x)]+3x=5(7x+4)-16

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Solution for 4[3-(2-8x)]+3x=5(7x+4)-16 equation: 


Simplifying
4[3 + -1(2 + -8x)] + 3x = 5(7x + 4) + -16
4[3 + (2 * -1 + -8x * -1)] + 3x = 5(7x + 4) + -16
4[3 + (-2 + 8x)] + 3x = 5(7x + 4) + -16

Combine like terms: 3 + -2 = 1
4[1 + 8x] + 3x = 5(7x + 4) + -16
[1 * 4 + 8x * 4] + 3x = 5(7x + 4) + -16
[4 + 32x] + 3x = 5(7x + 4) + -16

Combine like terms: 32x + 3x = 35x
4 + 35x = 5(7x + 4) + -16

Reorder the terms:
4 + 35x = 5(4 + 7x) + -16
4 + 35x = (4 * 5 + 7x * 5) + -16
4 + 35x = (20 + 35x) + -16

Reorder the terms:
4 + 35x = 20 + -16 + 35x

Combine like terms: 20 + -16 = 4
4 + 35x = 4 + 35x

Add '-4' to each side of the equation.
4 + -4 + 35x = 4 + -4 + 35x

Combine like terms: 4 + -4 = 0
0 + 35x = 4 + -4 + 35x
35x = 4 + -4 + 35x

Combine like terms: 4 + -4 = 0
35x = 0 + 35x
35x = 35x

Add '-35x' to each side of the equation.
35x + -35x = 35x + -35x

Combine like terms: 35x + -35x = 0
0 = 35x + -35x

Combine like terms: 35x + -35x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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